dissabte, 17 de gener del 2015

p:10 protein denaturation 1

DENATURATION:


Denaturation: Is a process in which proteins or nucleoids acids lose the quaternay tertiary and secondary structure that is present in their native state.Denaturation is the result of the application of some external stress(heat and pH change ) or compounds such as a strong acid or base a concentrated inorganic salt or organic solvent.

Objectives

1- Study the relation between the structure and the funcion of proteins.
2 - Understand how temperature,pH and salinity affect to the protein structure.

MATERIALS:
 2x250 ml beaker
4 test tube
Test tube rack
10ml pipet
Knife
Glass marking pen

Potato
Distilled water
Hydrogen Peroxide
NaCL
HCL

PROCEDURE


In this experiment we are going to test catalase activity in different environmet situation.We are going to mesure the rate of enzyme activity under various conditions ,such as different pH values and temperatures.We will measure catalase activity by observing the oxygen gas bubbles when H2O2 is destroyed .If lost of bubbles are produced, it means the reaction is happening quickly and the catalase enzyme is very active.

1 Prepare 30ml of H2O2 10% in a beaker
2 Prepare 30ml of  HCL10% in a beaker
3 Prepare 30ml of NaCL 50% in a beaker
4 Peel a fresh potato tuber and cut the tissue in five cubes of 1cm .Weigh them and equal the mass
5 Label 5 test tubes (1,2,3,4,5)
6 Immerse 10 minutes your piece of potato inside HCL beaker
7 Immerse 10 minutes another piece of potato inside NaOH beaker
8 Boil another piece of potato
9 With a mortar ,mash up the third piece of potato
10 Prepare 5 test tubes as indicated below:


TUBE
TREATMENT
Resuls potato+H2O2
Cm long potato+H2O2
1
Raw potato
treatment had not
6cm
2
Boiled potato
no bubbles have appeared
3,5cm
3    
Potato with HCL treatment
had to be almost no activity
3,8cm
4
Potato with NaCL treatment
been oxidized
3,4cm
5
Mashed up potato
to have more surface contact has more reaction
6,8 cm

11 Add 5ml H2O2 10% in each test tube
12 With a glass-marking pen mark the height of the bubbles.Measure it with a ruler
13 Compare the results of the 5 test tubes.

Complete the table below with the important parts of this experiments:





Parts:
In this experiment this was....
Independent variable
Treatment of each potato,pH,saliniti, temperature
Dependent variable
Height of the bubbles
Experimental group
2,3,4,5
Control groups
1
Constants
5ml H2O2, time , 1g of potato

Represent your results in a chart: Treatemer vs bubble's height:




QUESTIONS

1 How did the temperature of the potato affect the activity of catalase?
2 How did the change of pH of the potato affect the activity of catalase?
3 In which potato treatment was catalase the most active? Why do you think this was?
4 An experiment was performed to test the effect of temperature and pH on the activity of    Enzyme X.The following data was collected during the experiment:

a) What is the optium pH of enzyme X?
b)What is optium temperature of enzyme X?
c) Why do you think enzyme X has low activity at a pH of 10?
d)Enzyme X permoms critical life functions.Use the data adove to explain why a fever of 40 degrees may be dangerous.








Cap comentari:

Publica un comentari a l'entrada